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See, it would also never run using my code for 0, so the do while loop is the correct equivalent imo. [[User:Script 10k|Script 10k]] ([[User talk:Script 10k|talk]]) 00:17, 3 November 2017 (CET) | See, it would also never run using my code for 0, so the do while loop is the correct equivalent imo. [[User:Script 10k|Script 10k]] ([[User talk:Script 10k|talk]]) 00:17, 3 November 2017 (CET) | ||
Also I am thinking if the following code: | |||
schedule dprint("Is this annoying yet?") repeat 0 every 20; | |||
runs for long enough it could theoretically overflow with counter becoming negative and eventually reach 0 and stop, practically this can't ever happening because even if the counter would increase one 60 times per second it would need (2^31)*2/60/60/24 hours to reach zero (sorry if I'm doing bad the math but I am sure the number of hours it would take is just ridiculous). | |||