BSL talk:Manual: Difference between revisions
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Paradox-01 (talk | contribs) (new riddle) |
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'''iterate over something2 using somethingX''' | '''iterate over something2 using somethingX''' | ||
} | } | ||
---- | |||
:Wow, interesting. Although I don't think it matters that something2 and somethingX are undeclared, because BSL supports weak syntax. But why does it stop at 4? Hmm.... --[[User:Iritscen|Iritscen]] 17:21, 6 December 2009 (UTC) | |||
Revision as of 17:21, 6 December 2009
Tested this code in bio lab. Loop stops after displaying "riddle 4" for no reason. Strange enough: somethingX isn't declared but the code doesn't crash. Riddle me that. =D --Paradox-01 16:37, 6 December 2009 (UTC)
var int riddle_counter = 0;
func main
{
chr_wait_animtype 0 punch
#dmsg "Second test in bio lab."
BSL_chaos
}
func BSL_chaos
{
dmsg "hello?"
riddle_counter = riddle_counter + 1;
if (riddle_counter eq 1)
{
dmsg "[g.riddle 1]"
}
if (riddle_counter eq 2)
{
dmsg "[g.riddle 2]"
}
if (riddle_counter eq 3)
{
dmsg "[g.riddle 3]"
}
if (riddle_counter eq 4)
{
dmsg "[g.riddle 4]"
}
if (riddle_counter eq 5)
{
dmsg "[g.riddle 5]"
#dmsg "[r.ends here in compound level]"
}
if (riddle_counter eq 6)
{
dmsg "[g.riddle 6]"
}
sleep 60
something2 = BSL_chaos
iterate over something2 using somethingX
}
- Wow, interesting. Although I don't think it matters that something2 and somethingX are undeclared, because BSL supports weak syntax. But why does it stop at 4? Hmm.... --Iritscen 17:21, 6 December 2009 (UTC)